![]() Take v = 100 mph (44.2 m/s), r = 100 m q 63° (very steep).įour aluminum cubes of identical mass and surface polish are put on a turntable asĮach cube is on a different surface (smooth plastic, cork, rubber, sandpaper). Skaters race on a flat track: How do they get around the turns?īanking the Curve - gives a component of normal force towards the center of theĬircle Find q so that no frictional force is required to have ![]() If road conditions, tire conditions lower µ s, this can greatly reduce v max. When you speed the car up faster than v max , The centripetal force required to keep car going in circle is mv 2 /r. Provided by static friction between tires and road. Is the maximum speed the car can negotiate the curve at constant speed? (Take µ s = 1.2).ĭifferent from 0, therefore a F r differentįrom 0. If you swing a ball in a horizontal circle about your head, can the string be exactlyĪ car approaches a level, circular curve with R = 45.0 m. (If rotating in a vertical plane, launches a projectile with v ox. ![]() There are no forces on ball, therefore moves away with constant velocity v ox. If moving on a frictionless, horizontal surface, when string breaks, a r goes to 0. Holes), electric charge (proton attracts an electron = Hydrogen atom), FRICTION. What produces the force? strings, rubber bands, gravity (sun, earth, moon, black If T is the period of the motion = time for one revolution,īy N2, to accelerate requires an unbalanced force: Require this acceleration towards O to be: ![]() Therefore isįor circular motion with constant speed v, GEOMETRY and Kinematic equations Any object moving in a circle is always changing direction of motion. ![]()
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